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https://github.com/duanhf2012/origin.git
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新增自定义持久化的消息队列
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97
sysservice/messagequeueservice/MemoryQueue.go
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97
sysservice/messagequeueservice/MemoryQueue.go
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@@ -0,0 +1,97 @@
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package messagequeueservice
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import (
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"github.com/duanhf2012/origin/util/algorithms"
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"sync"
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)
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type MemoryQueue struct {
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subscriber *Subscriber
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topicQueue []TopicData
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head int32
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tail int32
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locker sync.RWMutex
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}
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func (mq *MemoryQueue) Init(cap int32) {
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mq.topicQueue = make([]TopicData, cap+1)
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}
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// 从队尾Push数据
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func (mq *MemoryQueue) Push(topicData *TopicData) bool {
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mq.locker.Lock()
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defer mq.locker.Unlock()
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nextPos := (mq.tail + 1) % int32(len(mq.topicQueue))
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//如果队列满了
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if nextPos == mq.head {
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//将对首的数据删除掉
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mq.head++
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mq.head = mq.head % int32(len(mq.topicQueue))
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}
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mq.tail = nextPos
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mq.topicQueue[mq.tail] = *topicData
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return true
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}
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func (mq *MemoryQueue) findData(startPos int32, startIndex uint64, limit int32) ([]TopicData, bool) {
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//空队列,无数据
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if mq.head == mq.tail {
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return nil, true
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}
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var findStartPos int32
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var findEndPos int32
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findStartPos = startPos //(mq.head + 1) % cap(mq.topicQueue)
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if findStartPos <= mq.tail {
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findEndPos = mq.tail + 1
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} else {
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findEndPos = int32(cap(mq.topicQueue))
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}
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//二分查找位置
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pos := int32(algorithms.BiSearch(mq.topicQueue[findStartPos:findEndPos], startIndex, 1))
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if pos == -1 {
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return nil, true
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}
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pos += findStartPos
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//取得结束位置
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endPos := limit + pos
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if endPos > findEndPos {
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endPos = findEndPos
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}
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return mq.topicQueue[pos:endPos], true
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}
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// FindData 返回参数[]TopicData 表示查找到的数据,nil表示无数据。bool表示是否不应该在内存中来查
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func (mq *MemoryQueue) FindData(startIndex uint64, limit int32) ([]TopicData, bool) {
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mq.locker.RLock()
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defer mq.locker.RUnlock()
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//队列为空时,应该从数据库查找
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if mq.head == mq.tail {
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return nil, false
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}
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/*
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//先判断startIndex是否比第一个元素要大
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headTopic := (mq.head + 1) % int32(len(mq.topicQueue))
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//此时需要从持久化数据中取
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if startIndex+1 > mq.topicQueue[headTopic].Seq {
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return nil, false
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}
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*/
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retData, ret := mq.findData(mq.head+1, startIndex, limit)
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if mq.head <= mq.tail || ret == true {
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return retData, true
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}
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//如果是正常head在后,尾在前,从数组0下标开始找到tail
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return mq.findData(0, startIndex, limit)
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}
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